Q32 of 63 Page 202

Find the equation of the hyperbola with

Foci , passing through (2, 3)

Foci = & passing through (2, 3)


As


Also, a2 = b2 (e2 - 1)


= b2e2 - b2


=


= 10 - b2


General Equation of Hyperbola is




As, this hyperbola passed through (2, 3)





4b2 - 9 (10 - b2) = -1(10 - b2) (b2)


4b2 – 90 + 9b2 = -10b2 + b4


b4 - 23b2 + 90 = 0


b4 - 18b2 - 5b2 + 90 = 0


b2(b2 - 18)- 5 (b2 - 18) = 0


(b2 - 5) (b2 - 18) =0


Either b2 = 5 or b2 = 18 (not possible, as a2 + b2 = 10)


a2 + b2 = 10


a2 + 5 = 10


a2 = 5



Hence, the required equation is .


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