If
, then find the value of n.
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i.e. ![]()

(∵a=3;d=2;a’=5;d’=3)

∴n(2+n) =7×5×37
∴n2+2n-1295=0
∴(n-35) (n+37) =0
∴ n=35 or n=-37 which is not possible as n is non negative.
So,n=35
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