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19. Arithmetic Progressions
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Q29 of 167 Page 19

In an A.P. the first term is 2, and the sum of the first 5 terms is one-fourth of the next 5 terms. Show that 20th term is - 112

given an AP whose first term is 2

To find: 20th term of an AP


It is given that the sum of the first five terms is one-fourth of the next 5 terms


So


20a + 40d = 5a + 35d


15a + 5d = 0


Substituting a as 2


We get d = - 6


Hence 20th term is a + 19d = - 112


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Find the sum of odd integers from 1 to 2001.

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If S1 be the sum of (2n + 1) terms of an A.P. and S2 sum of its odd terms, then prove that: S1: S2 = (2n + 1) : (n + 1).

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Questions · 167
19. Arithmetic Progressions
1 2 3 4 4 4 5 6 6 6 6 7 8 1 1 1 2 3 3 3 4 4 5 5 6 6 7 8 9 10 11 12 13 14 15 15 15 16 17 18 19 20 21 22 23 24 1 2 3 4 5 6 1 1 1 1 1 1 1 2 2 2 3 4 5 6 7 8 9 10 11 12 13 14 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 1 1 2 3 4 4 5 5 5 6 7 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 1 2 3 4 5 6 7 8 9 10 11 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
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