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19. Arithmetic Progressions
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Q7 of 167 Page 19

Show that the sum of all odd integers between 1 and 1000 which are divisible by 3 is 83667

according to given conditions the sequence is 3, 9, 15, 21….999

Given an AP whose first term is 3 and d is 6. Hence sum is given by


To prove: the sum of all odd integers between 1 and 1000 which are divisible by 3 is 83667


Hence the sum is given by the formula


Now for the finding number of terms, the formula is




n = 167


Substituting n is the sum formula we get



s = 83667


Hence, Proved.


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Questions · 167
19. Arithmetic Progressions
1 2 3 4 4 4 5 6 6 6 6 7 8 1 1 1 2 3 3 3 4 4 5 5 6 6 7 8 9 10 11 12 13 14 15 15 15 16 17 18 19 20 21 22 23 24 1 2 3 4 5 6 1 1 1 1 1 1 1 2 2 2 3 4 5 6 7 8 9 10 11 12 13 14 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 1 1 2 3 4 4 5 5 5 6 7 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 1 2 3 4 5 6 7 8 9 10 11 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
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