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19. Arithmetic Progressions
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Q4 of 167 Page 19

Insert six A.M.s between 15 and - 13.

Let A1, A2, A3, A4, A5, A6 be the 7 AM Between 15 And - 13


Then, 15, A1, A2, A3, A4, A5, A6, - 13 are in AP


We know,


An = a + (n - 1)d


A8 = - 13 = 15 + (8 - 1)d


d = -4


Hence,


A1 = a + d = 15 - 4 = 11


A2 = A1 + d = 11 - 4 = 7


A3 = A2 + d = 7 - 4 = 3


A4 = A3 + d = 3 - 4 = -1


A5 = A4 + d = -1 - 4 = -5


A6 = A5 + d = -5 - 4 = -9


More from this chapter

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2

Insert 4 A.M.s between 4 and 19.

3

Insert 7 A.M.s between 2 and 17.

5

There are n A.M.s between 3 and 17. The ratio of the last mean to the first mean is 3 : 1. Find the value of n.

6

Insert A.M.s between 7 and 71 in such a way that the 5th A.M. is 27. Find the number of A.M.s.

Questions · 167
19. Arithmetic Progressions
1 2 3 4 4 4 5 6 6 6 6 7 8 1 1 1 2 3 3 3 4 4 5 5 6 6 7 8 9 10 11 12 13 14 15 15 15 16 17 18 19 20 21 22 23 24 1 2 3 4 5 6 1 1 1 1 1 1 1 2 2 2 3 4 5 6 7 8 9 10 11 12 13 14 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 1 1 2 3 4 4 5 5 5 6 7 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 1 2 3 4 5 6 7 8 9 10 11 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
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