If x, y, z are in A.P. and A1is the A.M. of x and y, and A2 is the A.M. of y and z, then prove that the A.M. of A1 and A2 is y.
Given that,
A1 = AM of x and y
And A2 = AM of y and z
So, ![]()
![]()
AM of A1 and A2![]()

![]()
Since x, y, z are in AP, ![]()
Finally, AM = ![]()
Hence proved.
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