Q2 of 167 Page 19

If a2, b2, c2 are in A.P., prove that are in A.P.

If a2, b2, c2 are in A.P then, b2 - a2 = c2 - b2


If are in A.P. then,





Since, b2 - a2 = c2 - b2


Put b2 - a2= c2 - b2 in above,


We get LHS = RHS


Hence given terms are in AP


More from this chapter

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1

If are in A.P., prove that:

are in A.P.

1

If are in A.P., prove that:

a(b + c), b(c + a), c(a + b) are in A.P.

 3

If a, b, c are in A.P., then show that:

(i) a2(b + c), b2(c + a), c2(a + b) are also in A.P.


(ii) b + c - a, c + a - b, a + b - c are in A.P.


(iii) bc – a2, ca – b2, ab – c2 are in A.P.

 4

If are in A.P., prove that:

are in A.P.