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19. Arithmetic Progressions
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Q24 of 167 Page 19

Find the sum of n terms of the A.P. whose kth terms is 5k + 1

given an AP whose kth term is 5k + 1

To find: the sum of n terms of an AP whose kth term is 5k + 1


So substituting k = 1 to get the first term a1 = 6


Substituting k = 2 to get the second term a2 = 11


d = a2 - a1 = 5


we know that the sum of AP is given by the formula:



substituting the values in the above equation




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22

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23

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Find the sum of all two digit numbers which when divided by 4, yields 1 as the remainder.

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Questions · 167
19. Arithmetic Progressions
1 2 3 4 4 4 5 6 6 6 6 7 8 1 1 1 2 3 3 3 4 4 5 5 6 6 7 8 9 10 11 12 13 14 15 15 15 16 17 18 19 20 21 22 23 24 1 2 3 4 5 6 1 1 1 1 1 1 1 2 2 2 3 4 5 6 7 8 9 10 11 12 13 14 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 1 1 2 3 4 4 5 5 5 6 7 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 1 2 3 4 5 6 7 8 9 10 11 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
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