Q11 of 71 Page 41

You are repeating the Hershey-Chase experiment and are provided with two isotopes: 32P and 15N (in place of 35S in the original experiment). How do you expect your results to be different?

Use of 15N in place of 35S in the original experiment would not give any conclusive result because:

1. 32P is radioactive and 15N is non-radioactive. So, it’s presence won’t be detected.


2. If hypothetically 15N would be radioactive, then it’s presence would be seen both inside the cell as it gets incorporated in the DNA as nitrogenous base and also as a supernatant as it gets incorporated in the amino group of amino acids.


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