Q8 of 168 Page 5

ABC is a triangle in which = 90°, , BC = 12 cm and AC = 5 cm. Find the ratio of the areas of .

In Δ ANC and Δ ABC

<C = <C (Common)

<ANC = <BAC (Each 90°)

Then, Δ ANC ~ Δ ABC (By AA similarity)

By area of similarity triangle theorem.

Area of ΔABC/Area of ΔPQR = AC2 /BC2

Or, 52/122

Or, 25/144

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