Using Pythagoras theorem determine the length of AD in terms of b and c shown in Fig 4.219.

In
ABC
BC2=AB2+AC2
BC2=c2+b2
BC=
………………(i)
In
ABC and In
CBA
∠B= ∠B (Common)
∠ADB=∠BAC=90°
∴
ABD ~
CBA
∴ AB/CB=AD/CA
c/
=AD/b
AD=bc/![]()
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