A chord of a circle of radius 10 cm subtends a right angle at the centre. The length of the chord (in cm) is

Given A chord of a circle of radius 10 cm subtends a right angle at the centre.

We know that the Pythagoras theorem state that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Now, in right triangle OAB,

⇒ AB² = OA² + OB²

= 10² + 10²

= 100 + 100

= 200

∴ AB = 10√2 cm