Q6 of 168 Page 4

In an isosceles triangle ABC, AB = AC = 25 cm, BC = 14 cm. Calculate the altitude from A on BC.

We have,


AB=AC=25cm


BC=14cm


In ⊿ ACD and ⊿ ABD


∠ADB=∠ADB=90


AB=AC=25cm


AD=AD (Common)


⊿ ABD≅∠ACD


∴BD=CD=7cm (By c.p.c.t)


In ⊿ACD


AB2=AD2+BD2


252=AD2+72


625=AD2+49


AD2=625-49


AD2=576


AD=


AD=24 cm


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