Q15 of 168 Page 4

Each side of a rhombus is 10 cm. If one of its diagonals is 16 cm find the length of the other diagonal.

We have,

ABCD is a rhombus with side 10 cm and diagonal BD=16 CM

We know that rhombus of diagonal bisects each other at 90

BO=OD=8cm

In AOB

AB²=AO²+BO²

10²= AO² +8²

100= AO²+64

AO²=100-64

AO²=36

AO=

AO=6 cm

∴ AC=AO+OC

AC=6+6

AC=12 cm

In a , AB = BC = CA = 2 a and . Prove that

(i) (ii) Area () =

The lengths of the diagonals of a rhombus are 24 cm and 10 cm. Find each side of the rhombus.

In an acute-angled triangle, express a median in terms of its sides.

Calculate the height of an equilateral triangle each of whose sides measures 12 cm.