Q38 of 168 Page 4

If such that DE = 3 cm, EF = 2 cm, DF = 2.5 cm, BC = 4 cm, then perimeter of is

Given that ΔABC and ΔDEF are similar triangles such that AB = 3 cm, DE = 3 cm, DF = 2.5 cm and EF = 2 cm.


We know that two triangles are similar if their corresponding sides are proportional.



First consider,




⇒ AB = 6 cm … (1)


Now,




⇒ CA = 5 cm … (2)


Then, perimeter of ΔABC = AB + BC + CA = 6 + 4 + 5


∴ Perimeter of ΔABC = 15 cm

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