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. such that ar (
) = 4 ar (
). If BC =12 cm, then QR =
Given ar (ΔABC) ~ ar (PQR) such that ar (ΔABC) = 4 ar (ΔPQR) and BC = 12 cm
We know that ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.

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∴ QR = 6 cm
Couldn't generate an explanation.
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