In a , = 90°, AB = 5 cm and AC = 12 cm. If , then AD =

Given in ΔABC, ∠A = 90°, AB = 5 cm, AC = 12 cm and AD ⊥ BC

In ΔACB and ΔADC,

∠CAB = ∠ADC [90°]

∠ABC = ∠CAD [corresponding angles]

∠C = ∠C [common angle]

We know that AAA similarity criterion states that in two triangles, if corresponding angles are equal, then their corresponding sides are in the same ratio and hence the two triangles are similar.

∴ ΔACB ~ ΔADC

∴ AD = 60/13 cm