Q14 of 109 Page 300

In the adjoining figures, and are perpendiculars to the diagonal of a ||gm Prove that

(i) (ii)


Here, ABCD is parallelogram.


Hence, AD || BC and AD = BC


(i) In ∆ALD and ∆CMB, we have,
AD = BC


∠​ALD = ∠​CMB (90o each)


∠​ADL = ∠​CBM (Alternate interior angle)
∴ ∆ALD ≅ ∆CMB


(ii) As ∆ALD ≅ ∆CMB …from 1
∴​ AL = CM …by cpct


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