Q7 of 109 Page 318

The length of each side of a rhombus is 10cm and one of its diagonals is of length 16 cm. The length of the other diagonal is

It is given in the question that,

ABCD is rhombus where, AB = BC = CD = DA


Now, by using Pythagoras theorem in triangle BOC we have:


BC2 = OB2 + OC2


(10)2 = OB2 + (8)2


100 = OB2 + 64


OB2 = 100 – 64


OB2 = 36


OB = 6 cm


∴ Length of diagonal, BC = OB + OD


BC = 6 + 6


BC = 12 cm


Hence, option (B) is correct

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