Q18 of 109 Page 318

If one angle of a parallelogram is 24o less than twice the smallest angle, then the largest angle of the parallelogram is

As per the question,

Let the smallest angle be x° and the largest angle be (2x – 24)°


Since, the sum of adjacent angles of a parallelogram is 180°


∴ x + (2x – 24) = 180°


3x – 24 = 180°


x = 68°


Hence, the largest angle is: 2x – 24 = 2(68) – 24 = 136 – 24 = 112


∴Option A is correct

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