In the adjoining figures,
is a parallelogram. If
and
are points on
and
respectively such that
and
prove that
is a parallelogram.

ABCD is parallelogram
We know that opposite sides and angles of parallelogram are equal.
∴ ∠B = ∠D and AD = BC and AB = DC
Also, AD || BC and AB|| DC
It is given that
and ![]()
Hence, AP = CQ … ∵ AD = BC
In ∆DPC and ∆BQA, we have,
AB = CD
∠B = ∠D
DP = QB … as
and ![]()
Hence, by SAS test for congruency,
∆DPC ≅ ∆BQA
∴ PC = QA … by cpct
Hence, from above, in AQCP, we have,
AP = CQ and PC = QA
∴ AQCP is a parallelogram.
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