Q25 of 109 Page 318

In the given figure, ABCD is a rhombus. Then,

Since, we know that the diagonals of a rhombus bisect each other at 90°.

Hence, OA = AC, OB = BD and ∠AOB = 90°

AB² = OA² + OB²

AB² = ( AC)² + ( BD)²

= (AC)² + (BD)²

AB² = (AC² + BD²)

4AB² = (AC² + BD²)

∴ Option C is correct

In a trapezium ABCD, if E and F be the mid-point of the diagonals AC and BD respectively. Then, EF = ?

In the given figure, ABCD is a parallelogram, M is the mid-point of BD and BD bisects ∠B as well as ∠D. Then, ∠AMB = ?

In a trapezium ABCD, if AB || CD, then (AC² + BD²) = ?

Two parallelograms stand on equal bases and between the same parallels. The ratio of their areas is