Q24 of 109 Page 318

In the given figure, ABCD is a parallelogram, M is the mid-point of BD and BD bisects ∠B as well as ∠D. Then, ∠AMB = ?

Since, ABCD is a parallelogram,

∴∠B = ∠D (opposite angle)


1/2 ∠B = 1/2 ∠D


∠ADB = ∠ABD


∴ ADB is an isosceles triangle.


Since, M is the midpoint of BD


∴ AM is a median of ΔADB.


Now, ∠AMB = 90° (AM is perpendicular to BD)


∴Option C is correct

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