Q10 of 109 Page 318

The bisectors of any two adjacent angles of a parallelogram intersect at

We know that,

Sum of two adjacent angles = 180^o

Also, sum of bisector of adjacent angles = 180/2 = 90^o

As sum of angles of a triangle = 180^o

∴ Sum of 2 adjacent angles + Intersection angle = 180^o

90^o + Intersection angle = 180^o

∴ Intersection angle = 180^o – 90^o

= 90^o

Hence, option (D) is correct

If ABCD is a parallelogram with two adjacent angles ∠A = ∠ B, then the parallelogram is a

In a quadrilateral ABCD, if AO and BO are the bisectors of ∠A and ∠B respectively, ∠C = 70° and ∠D = 30°. Then, ∠AOB = ?

The bisectors of the angles of a parallelogram enclose a

The figure formed by joining the mid-points of the adjacent sides of a quadrilateral is a