The diagonals of a rectangle ABCD intersect at the point O. If ∠BOC = 50°, then ∠OAD = ?

∠BOC = ∠AOD (Vertically opposite angles)
Angle AOD = 50°
In ∆ AOD, Since, the diagonals are equal, thus the bisectors will also be equal)
Thus, OA = OD
∴ ∠OAD = ∠ODA
=
(180° - 50°)
=
(130°)
= 65°
∴ Option C is correct
Couldn't generate an explanation.
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