Q1 of 178 Page 533

Determine k so that (3k - 2), (4k - 6) and (k + 2) are three consecutive terms of an AP.

Since, the terms are in an AP, therefore

(4k - 6) - (3k - 2) = (k + 2) - (4k - 6)


⇒ k - 4 = - 3k + 8


⇒ 4k = 12


⇒ k = 3


∴ k = 3


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