Q5 of 178 Page 548

If the numbers (2n – 1), (3n + 2) and (6n – 1) are in AP, find the value of n and the numbers.

Since, the terms are in an AP, therefore

(3n + 2) - (2n - 1) = (6n - 1) - (3n + 2)


⇒ n + 3 = 3n - 3


⇒ 2n = 6


⇒ n = 3


∴ n= 3, and hence the numbers are 5, 11, 17.


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