If the sum of first m terms of an AP is (2m² + 3m) then what is its second term?

Let S_n denotes the sum of first n terms of an AP.

Sum of first m terms = S_m = 2m² + 3m

Then n^th term is given by: a_n = S_n - S_{n - 1}

We need to find the 2^nd term, so put n = 2, we get

a₂ = S₂ - S₁

= (2(2)² + 3(2)) - (2(1)² + 3(1))

= 14 - 5

= 9

∴ the second term of the AP is 9.