Q3 of 178 Page 533

If (3y - 1), (3y + 5) and (5y + 1) are three consecutive terms of an AP then find the value of y.

Since, the terms are in an AP, therefore

(3y + 5) - (3y - 1) = (5y + 1) - (3y + 5)


⇒ 6 = 2y - 4


⇒ 2y = 10


⇒ y = 5


∴ y = 5


More from this chapter

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1

Determine k so that (3k - 2), (4k - 6) and (k + 2) are three consecutive terms of an AP.

 2

Find the value of x for which the numbers (5x + 2), (4x - 1) and (x + 2) are in AP.

 4

Find the value of x for which (x + 2), 2x, (2x + 3) are three consecutive terms of an AP.

 5

Show that (a - b)2, (a2 + b2) and (a + b)2 are in AP.