Q1 of 178 Page 548

The first three terms of an AP are respectively (3y – 1), (3y + 5) and (5y + 1), find the value of y.

Since, the terms are in an AP, therefore

(3y + 5) - (3y - 1) = (5y + 1) - (3y + 5)


⇒ 6 = 2y - 4


⇒ 2y = 10


⇒ y = 5


∴ y = 5


More from this chapter

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12

Divide 32 into four parts which are the four terms of an AP such that the product of the first and the fourth terms is to the product of the second and the third terms as 7 : 15.

 13

The sum of first three terms of an AP is 48. If the product of first and second terms exceeds 4 times the third term by 12. Find the AP.

 2

If k, (2k – 1) and (2k + 1) are the three successive terms of an AP, find the value of k.

 3

If 18, a, (b – 3) are in AP, then find the value of (2a – b).