Q2 of 46 Page 1

In figure 1, a tower AB is 20 m high and BC, its shadow on the ground, is 20√3 m long. Find the Sun’s altitude.


Given


Height of tower, AB = 20 m


Length of shadow,


Altitude of sun means we have to calculate the angle of elevation of the top of the tower from the tip of the shadow.


Let altitude = ∠ACB = θ


Now In triangle ABC



→ θ = 30°


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