Q10 of 46 Page 1

Solve the following quadric equation for x:

x2 – 2ax – (4b2 – a2) = 0

Equation can be re - written as


x2 + (2b - a)x - (2b + a)x - (2b - a)(2b + a) = 0 [ as x2 - y2 = (x + y) (x - y) ]


x(x + 2b - a) - (2b + a)(x + 2b - a) = 0


(x - (2b + a))(x + 2b - a) = 0


x = 2b + a or x = a - 2b


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