The diagonal of a rectangular field is 16 meters more than the shorter side. If the longer side is 14 meters more than the shorter side, then find the lengths of the sides of the field.

Let the shortest side be x
Length of diagonal = x + 16
Length of longer side = x + 14
As this triangle is a right angled triangle it should verify the phythagoras theorem
i.e. (hypotenuse)2 = (base)2 + (perpendicular)2
(x + 16)2 = (x + 14)2 + x2
x2 + 32x + 256 = x2 + 196 + 28x + x2
x2 - 4x - 60 = 0
x2 - 10x + 6x - 60 = 0
x(x - 10) + 6(x - 10) = 0
(x + 6)(x - 10) = 0
x = - 6 [ not possible as length of a side can't be negative ]
or x = 10
so length of longer side of field, x + 14 = 10 + 14 = 24 m
length of shorter side, x = 10 m
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