The 4th term of an AP is twice its 18th term. If its 6th term is - 8, then find the sum of its first 20 terms.
Let the a be first term and d be the common difference of AP
Given
a4 = 2a18
using nth term formula i.e. an = a + (n - 1)d
a + 3d = 2(a + 17d)
a + 3d = 2a + 34d
a + 31d = 0
a = - 31d [1]
Also,
a6 = - 8
a + 5d = - 8
- 31d + 5d = - 8 [using 1]
- 26d = - 8
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Also sum of first n terms of an AP is
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