Prove that the lengths of the tangents drawn from an external point to a circle are equal.

Given : A circle with center O , two tangents PT and PQ are drawn from an external point P
to the points T and Q on circle.
To prove : PT = PQ
Construction : Join OP
Proof :
In △POT and △POQ
OT = OQ [radii of same circle]
∠PTO = ∠PQO = 90° [tangent drawn at a point on a circle is perpendicular to the radius through point of contact]
OP = OP [common]
△POT ≅ △POQ [By RHS criterion]
PT = PQ [By CPCT]
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.