Q7 of 46 Page 1

Solve the following quadric equation for x :

4x2 + 4bx – (a2 – b2) = 0

Equation can be re - written as


4x2 + 4bx + (b2 – a2) = 0


4x2 + 2(b - a)x + 2(b + a)x + (b - a)(b + a) = 0 [ as x2 - y2 = (x + y) (x - y) ]


2x(2x + b - a) + (b + a)(2x + b - a) = 0


(2x + b + a)(2x + b - a) = 0




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