Q3 of 44 Page 50

If p(t) t3 – 1, find the values of p(1),p(-1),P(0),p(2),p(-2).

P(t) = t3 – 1

Therefore,


P(1) = 13 – 1


⇒ P(1) = 1 – 1


⇒ P(1) = 0


P(-1) = (-1)3 – 1


⇒ P(-1) = -1 – 1


⇒ P(-1) = -2


P(0) = 03 – 1


⇒ P(0) = 0 – 1


⇒ P(0) = -1


P(2) = 23 – 1


⇒ P(2) = 8 – 1


⇒ P(2) = 7


P(-2) = (-2)3 – 1


⇒ P(2) = -8 – 1


⇒ P(2) = -9


More from this chapter

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1

If p(x) = 5x7 – 6x5 + 7x - 6, find

(i) coefficient of x5


(ii) degree of p(x)


(iii) constant term.

 2

State which of the following statements are true and which are false? Give reasons for your choice.

(i) The degree of the polynomial is


(ii) The coefficient of x2 in the polynomial p(x) = 3x3 – 4x2 + 5x + 7 is 2.


(iii) The degree of a constant term is zero.


(iv) is a quadratic polynomial.


(v) The degree of a polynomial is one more than the number of terms in it.

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