Q2 of 44 Page 70

Check in which case the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial.

t2 – 3, 2t4 + 3t3 – 2t2 – 9t - 12

p(x) = 2t4 + 3t3 – 2t2 - 9t – 12

g(x) = t2 – 3


On dividing them,



The remainder is 0


Hence, yes t2 – 3 is a factor of 2t4 + 3t3 – 2t2 - 9t – 12

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