Find the quadratic polynomial in each case, with the given numbers as the sum and product of its zeroes respectively.
4, 1
Given: α + β = 4
αβ = 1
Let the quadratic polynomial be ax2 + bx + c …(1)
Where, a≠0
And zeroes of the polynomial are α and β.
Now we know that,
![]()
And,
![]()
![]()
If a = 1
![]()
⇒ b = -4 …(2)
⇒c = 1 …(3)
From (2) and (3),
a = 1, b = -4 and c = 1
Hence, the polynomial is x2 - 4x + 1
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.