Find the quadratic polynomial in each case, with the given numbers as the sum and product of its zeroes respectively.

Given: α + β = √2
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Let the quadratic polynomial be ax2 + bx + c …(1)
Where, a≠0
And zeroes of the polynomial are α and β .
Now we know that,
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And,
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If a = 3
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⇒ b = -3√2 …(2)
⇒c = 1 …(3)
From (2) and (3),
a = 3, b = -3 √2 and c = 1
Hence, the polynomial is 3x2 – 3√2x + 1
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