Q2 of 44 Page 70

Check in which case the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial.

x2 - 3x + 1, x5 - 4x3 + x2 + 3x + 1

p(x) = x5 – 4x3 + x2 + 3x + 1

g(x) = x3 – 3x + 1

On dividing them,


The remainder is 2 ≠ 0

Hence, no x3 – 3x + 1 is not a factor of x5 – 4x3 + x2 + 3x + 1

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Check in which case the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial.

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Check in which case the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial.

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Obtain all other zeroes of 3x4 + 6x3 – 2x2 – 10x – 5,

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4

On dividing x3 – 3x2 + x + 2 by a polynomial g(x), the quotient and remainder were x - 2 and – 2x + 4 respectively. Find g(x)