Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.
x2 – 2x – 8
p(x) = 0
⇒ x2 – 2x – 8 = 0
⇒ x2 + 2x – 4x – 8 = 0
⇒ x(x + 2) – 4(x + 2) = 0
⇒ (x + 2)(x – 4) = 0
⇒ x = -2 and x = 4
Hence, -2 and 4 are zeroes of the polynomial x2 – 2x – 8.
Now,
Sum of zeroes = -2 + 4
⇒ Sum of zeroes = 2
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Product of zeroes = -2 × 4
⇒ Product of zeroes = -8
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