Obtain all other zeroes of 3x4 + 6x3 – 2x2 – 10x – 5,
if two of its zeroes are
and ![]()
Two zeroes are
and ![]()
is a factor
is a factor
is a factor
Now,

Therefore, 3x2 + 6x +3 is also a factor
Dividing 3x2 + 6x +3 by 3,
We get,
x2 + 2x +1
Factorising x2 + 2x +1,
x2 + 2x +1 = 0
⇒ x2 + x + x +1 = 0
⇒ x(x+ 1) + 1(x +1) = 0
⇒ (x+ 1)(x +1) = 0
⇒ x= -1, -1
Therefore, the other zeroes are -1 and -1.
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