In right angle triangle ABC, 8 cm, 15 cm and 17 cm are the lengths of AB, BC and CA respectively. Then, find out sin A, cos A and tan A.
We have

Given: ∠ABC = 90°, AB = 8 cm, BC = 15 cm and CA = 17 cm
We know sin A is given by,
![]()
⇒
[∵, perpendicular is the side opposite to the angle A & hypotenuse is the side opposite to the right angle of that triangle]
⇒
…(i)
Also, cos A is given by
![]()
⇒ ![]()
⇒
…(ii)
Now, tan A can be found out by two ways:
Method 1: tan A is given by,
![]()
⇒ ![]()
⇒ ![]()
Method 2: tan A can also be written as,
![]()
⇒
[from equations (i) & (ii)]
⇒ ![]()
Thus,
,
and
.
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