Q6 of 46 Page 284

In right angle is at Y, YZ = x and XZ = 2x then determine YXZ and YZX.

We have


With given values, YZ = x and XZ = 2x, we can find out both angles.


For YXZ:


Let YXZ = θ, then





θ = sin-1(1/2)


θ = 30° [, sin 30° = 1/2]


For YZX = α, then





α = cos-1(1/2)


α = 60° [, cos 60° = 1/2]


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