Evaluate the following :
C. (sec2θ – 1) (cosec2θ – 1)
We have
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⇒ ![]()
⇒
[∵, (1 – cos2 θ) = sin2 θ & (1 – sin2 θ = cos2 θ]
⇒ (sec2 θ – 1)(cosec2 θ – 1) = 1
Thus, (sec2 θ – 1)(cosec2 θ – 1) = 1.
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