Q4 of 46 Page 277

If then find sin A and tan A

Given that,


But



base = 12 and hypotenuse = 13


So, using Pythagoras theorem, we can say


(hypotenuse)2 = (perpendicular)2 + (base)2


(perpendicular)2 = (hypotenuse)2 – (base)2


(perpendicular)2 = (13)2 – (12)2


(perpendicular)2 = 169 – 144 = 25


perpendicular = √25 = 5


Using perpendicular = 5, base = 12 and hypotenuse = 13, we can find out sin A and tan A.


Sin A is given by




And, tan A is given by




Thus, and .


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