Evaluate the following :
A. (1 + tanθ + secθ)(1 + cotθ – cosecθ)
We have
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⇒ ![]()
⇒ 
⇒
[∵, (a + b)(a – b) = a2 – b2]
⇒
[∵, (a + b)2 = a2 + b2 + 2ab]
⇒
[∵, sin2 θ + cos2 θ = 1]
⇒ ![]()
Thus, (1 + tan θ + sec θ)(1 + cot θ – cosec θ) = 2.
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