Q8 of 46 Page 277

In a right angle triangle ABC, right angle is at B, if then find the value of

B. cos A cos C – sin A sin C

To find: cos A cos C – sin A sin C.


From previous part of the question, we have






Using these values, we get


cos A cos C – sin A sin C =


⇒ cos A cos C – sin A sin C = √3/4 - √3/4 = 0


Thus, cos A cos C – sin A sin C = 0.


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