In ΔABC, m∠B = 90,
, M
. If AM — MC = 7, AB2 — BC2 = 175, find AC.

m
B = 90
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AM — MC = 7
Applying Pythagoras theorem in ΔABM and ΔCBM
AB2 = BM2 + AM2 …Equation (i)
BC2 = BM2 + MC2 …Equation (ii)
Subtracting Equation (ii) from Equation (i) we get
AB2 – BC2 = AM2 – MC2
⇒ (AM – MC)(AM + MC) = AB2 – BC2
Putting the values we get :
7 × (AM + MC) = 175
⇒ AM + MC = 25
⇒ AC = 25
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